About Dice Games (with.Java)

In this article, we learned about dice games (with.Java)

We’re going to learn by solving a coding test problem, doing a retrospective on the problem we solved, and looking at other ways to solve it. Let’s start with the problem.

Problem

You have three dice with the numbers 1 through 6 written on them. Let’s call the numbers that come up when you roll the three dice A, B, and C respectively.

If all three numbers are different, you get a score of A + B + C. If any two of the three numbers are the same and the other two are different, you get (a + b + c) × (a2 + b2 + c2 ). If all three numbers are equal, score (a + b + c) × (a2 + b2 + c2 ) × (a3 + b3 + c3 ). Write a solution function that returns the number of points you get when given three integers a, b, and c as parameters.

Example input and output

a: 2 b: 6 c: 1 result: 9

In other words, in example 1, all three dice numbers are different, so we get 2 + 6 + 1 = 9. Therefore, we return 9.

My solution to the problem

class Solution {
    public int solution(int a, int b, int c) {
        int answer = 0;
        if(a != b && a != c && b != c){
            answer = a + b + c;
        } else if(a == b && a != c || a == c && b != c || b == c && a != b ){
            answer = (a + b + c) * ((int)Math.pow(a,2) + (int)Math.pow(b,2) + (int)Math.pow(c,2));
        } else {
            answer = (a + b + c) * ((int)Math.pow(a,2) + (int)Math.pow(b,2) + (int)Math.pow(c,2)) * ((int)Math.pow(a,3) + (int)Math.pow(b,3) + (int)Math.pow(c,3));
        }
        return answer;
    }
}

Solution Explanation

In the code I wrote, there are 3 main cases that I wrote to allow me to perform an operation based on a condition. In the first case, I made it possible to perform the operation A+B+C if A and B are not equal, A and C are not equal, and B and C are not equal. For the 2nd condition, we used the Math.pow function for powers so that we could perform the operation (a + b + c) × (a2 + b2 + c2 ) if a and b are equal and a and c are not equal, or if a and c are equal but b and c are not equal, or if b and c are equal but a and b are not equal. The function returned as a double, so we prefixed it with an int. The last condition is that a == b == c, which would otherwise be the case, so in this case, (a + b + c) × (a2 + b2 + c2 ) × (a3 + b3 + c3 ) to perform the corresponding operation.