How to find the nearest 1, output the number that meets a condition via a given index (with.Java)

In this article, About Find the nearest 1, outputting the number fulfilling the condition through a given index (with.Java)

We’re going to be solving a coding test problem, doing a retrospective on the problem we solved, and learning about other ways to solve it.

Let’s start with the problem

Problem

You are given an array of integers, arr. The elements of arr are either 1 or 0. Complete a solution function that, given an integer idx, finds and returns the smallest index in arr that is greater than idx and has a value of 1.

However, if there is no such index, return -1.

Example input and output

my_string: [0, 0, 0, 0, 1]

idx: 1

result: 3

The smallest index that is greater than 1 and has an element of 1 is 3. Therefore, it returns 3.

My solution to the problem

class Solution {
    public int solution(int[] arr, int idx) {
        for(int i = idx; i < arr.length; i++) {
            if(arr[i] == 1) {
                return i;
            }
        }
        return -1;
    }
}

Solution Description

This class defines a solution method that performs the following operations on a given array of integers arr and an integer idx:

Performs a loop from idx to the end of arr. IDX is the starting index, which means that it starts at this position in ARR and traverses to the end of the array.

Within the loop, we check to see if the value of arr[i] at the current index i is 1. If arr[i] is 1, return i and exit the method. This is equivalent to finding the first index above idx that has a value of 1.

If the iteration completes and no index with a value of 1 was found, return -1. This is true if, as required by the problem, there is no index in the array with a value of 1 that is greater than idx.

For example, if arr is [1, 1, 1, 1, 1, 0] and idx is 3, we would return 3 as the result because the first index with a value of 1 starting at idx is 3.